Tap the blue circles to see an explanation.
| $$ \begin{aligned}3y+\frac{5}{3}y+12& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(3+\frac{5}{3})y+12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{14}{3}y+12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{14y}{3}+12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{14y+36}{3}\end{aligned} $$ | |
| ① | Use the distributive property. |
| ② | Combine like terms |
| ③ | Multiply $ \dfrac{14}{3} $ by $ y $ to get $ \dfrac{ 14y }{ 3 } $. Step 1: Write $ y $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{14}{3} \cdot y & \xlongequal{\text{Step 1}} \frac{14}{3} \cdot \frac{y}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 14 \cdot y }{ 3 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 14y }{ 3 } \end{aligned} $$ |
| ④ | Add $ \dfrac{14y}{3} $ and $ 12 $ to get $ \dfrac{ \color{purple}{ 14y+36 } }{ 3 }$. Step 1: Write $ 12 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |