Question
Answer
$$3x\cdot2+65x-\dfrac{3}{3}x\cdot3-12x\cdot5x-3=-60x^2+68x-3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3x\cdot2+65x-\frac{3}{3}x\cdot3-12x\cdot5x-3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x+65x-\frac{3}{3}x\cdot3-60x^2-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}71x-\frac{3}{3}x\cdot3-60x^2-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}71x - \frac{ 3 : \color{orangered}{ 3 } }{ 3 : \color{orangered}{ 3 }} \cdot x \cdot 3 - 60x^2 - 3 \xlongequal{ } \\[1 em] & \xlongequal{ }71x-\frac{1}{1}x\cdot3-60x^2-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}71x-x\cdot3-60x^2-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}68x-60x^2-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle6}{\textcircled {6}} } }}}-60x^2+68x-3\end{aligned} $$ | |
| ① | $$ 3 x \cdot 2 = 6 x $$$$ 12 x \cdot 5 x = 60 x^{1 + 1} = 60 x^2 $$ |
| ② | Combine like terms: $$ \color{blue}{6x} + \color{blue}{65x} = \color{blue}{71x} $$ |
| ③ | Divide both the top and bottom numbers by $ \color{orangered}{ 3 } $. |
| ④ | Remove 1 from denominator. |
| ⑤ | Combine like terms: $$ \color{blue}{71x} \color{blue}{-3x} = \color{blue}{68x} $$ |
| ⑥ | Combine like terms: $$ -60x^2+68x-3 = -60x^2+68x-3 $$ |
This page was created using
Simplify Rational Expressions