Tap the blue circles to see an explanation.
| $$ \begin{aligned}3 \cdot \frac{x^3}{12}x^2+9x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3x^3}{12}x^2+9x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{3x^5}{12}+9x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{3x^5+108x}{12}\end{aligned} $$ | |
| ① | Multiply $3$ by $ \dfrac{x^3}{12} $ to get $ \dfrac{ 3x^3 }{ 12 } $. Step 1: Write $ 3 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 3 \cdot \frac{x^3}{12} & \xlongequal{\text{Step 1}} \frac{3}{\color{red}{1}} \cdot \frac{x^3}{12} \xlongequal{\text{Step 2}} \frac{ 3 \cdot x^3 }{ 1 \cdot 12 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 3x^3 }{ 12 } \end{aligned} $$ |
| ② | Multiply $ \dfrac{3x^3}{12} $ by $ x^2 $ to get $ \dfrac{ 3x^5 }{ 12 } $. Step 1: Write $ x^2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{3x^3}{12} \cdot x^2 & \xlongequal{\text{Step 1}} \frac{3x^3}{12} \cdot \frac{x^2}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 3x^3 \cdot x^2 }{ 12 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 3x^5 }{ 12 } \end{aligned} $$ |
| ③ | Add $ \dfrac{3x^5}{12} $ and $ 9x $ to get $ \dfrac{ \color{purple}{ 3x^5+108x } }{ 12 }$. Step 1: Write $ 9x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |