Tap the blue circles to see an explanation.
| $$ \begin{aligned}3 \cdot \frac{x^2}{14}x^2-7x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3x^2}{14}x^2-7x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{3x^4}{14}-7x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{3x^4-98x}{14}\end{aligned} $$ | |
| ① | Multiply $3$ by $ \dfrac{x^2}{14} $ to get $ \dfrac{ 3x^2 }{ 14 } $. Step 1: Write $ 3 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 3 \cdot \frac{x^2}{14} & \xlongequal{\text{Step 1}} \frac{3}{\color{red}{1}} \cdot \frac{x^2}{14} \xlongequal{\text{Step 2}} \frac{ 3 \cdot x^2 }{ 1 \cdot 14 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 3x^2 }{ 14 } \end{aligned} $$ |
| ② | Multiply $ \dfrac{3x^2}{14} $ by $ x^2 $ to get $ \dfrac{ 3x^4 }{ 14 } $. Step 1: Write $ x^2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{3x^2}{14} \cdot x^2 & \xlongequal{\text{Step 1}} \frac{3x^2}{14} \cdot \frac{x^2}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 3x^2 \cdot x^2 }{ 14 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 3x^4 }{ 14 } \end{aligned} $$ |
| ③ | Subtract $7x$ from $ \dfrac{3x^4}{14} $ to get $ \dfrac{ \color{purple}{ 3x^4-98x } }{ 14 }$. Step 1: Write $ 7x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |