Tap the blue circles to see an explanation.
| $$ \begin{aligned}3(x+2)-11x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x+6-11x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-8x+6\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( x+2\right) $ $$ \color{blue}{3} \cdot \left( x+2\right) = 3x+6 $$ |
| ② | Combine like terms: $$ \color{blue}{3x} +6 \color{blue}{-11x} = \color{blue}{-8x} +6 $$ |