Tap the blue circles to see an explanation.
| $$ \begin{aligned}2y^2+9y+\frac{4}{4}y^2-4y-3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2y^2+9y + \frac{ 4 : \color{orangered}{ 4 } }{ 4 : \color{orangered}{ 4 }} \cdot y^2 - 4y - 3 \xlongequal{ } \\[1 em] & \xlongequal{ }2y^2+9y+\frac{1}{1}y^2-4y-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2y^2+9y+y^2-4y-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}3y^2+9y-4y-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}3y^2+5y-3\end{aligned} $$ | |
| ① | Divide both the top and bottom numbers by $ \color{orangered}{ 4 } $. |
| ② | Remove 1 from denominator. |
| ③ | Combine like terms: $$ \color{blue}{2y^2} +9y+ \color{blue}{y^2} = \color{blue}{3y^2} +9y $$ |
| ④ | Combine like terms: $$ 3y^2+ \color{blue}{9y} \color{blue}{-4y} -3 = 3y^2+ \color{blue}{5y} -3 $$ |