Question
Answer
$$2x-3(x+2(x-(x+5))+1)=-x+27$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2x-3(x+2(x-(x+5))+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x-3(x+2(x-x-5)+1) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x-3(x+2\cdot(-5)+1) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}2x-3(x-10+1) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}2x-3(x-9) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}2x-(3x-27) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle6}{\textcircled {6}} } }}}2x-3x+27 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle7}{\textcircled {7}} } }}}-x+27\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( x+5 \right) = -x-5 $$ |
| ② | Combine like terms: $$ \, \color{blue}{ \cancel{x}} \, \, \color{blue}{ -\cancel{x}} \,-5 = -5 $$ |
| ③ | $$ 2 \cdot -5 = -10 $$ |
| ④ | Combine like terms: $$ x \color{blue}{-10} + \color{blue}{1} = x \color{blue}{-9} $$ |
| ⑤ | Multiply $ \color{blue}{3} $ by $ \left( x-9\right) $ $$ \color{blue}{3} \cdot \left( x-9\right) = 3x-27 $$ |
| ⑥ | Remove the parentheses by changing the sign of each term within them. $$ - \left( 3x-27 \right) = -3x+27 $$ |
| ⑦ | Combine like terms: $$ \color{blue}{2x} \color{blue}{-3x} +27 = \color{blue}{-x} +27 $$ |
This page was created using
Simplify Rational Expressions