Tap the blue circles to see an explanation.
| $$ \begin{aligned}2x^2+9x-\frac{5}{2}x^2+16x+30& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2+9x-\frac{5x^2}{2}+16x+30 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-x^2+18x}{2}+16x+30 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{-x^2+50x}{2}+30 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{-x^2+50x+60}{2}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{5}{2} $ by $ x^2 $ to get $ \dfrac{ 5x^2 }{ 2 } $. Step 1: Write $ x^2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{5}{2} \cdot x^2 & \xlongequal{\text{Step 1}} \frac{5}{2} \cdot \frac{x^2}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 5 \cdot x^2 }{ 2 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 5x^2 }{ 2 } \end{aligned} $$ |
| ② | Subtract $ \dfrac{5x^2}{2} $ from $ 2x^2+9x $ to get $ \dfrac{ \color{purple}{ -x^2+18x } }{ 2 }$. Step 1: Write $ 2x^2+9x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |
| ③ | Add $ \dfrac{-x^2+18x}{2} $ and $ 16x $ to get $ \dfrac{ \color{purple}{ -x^2+50x } }{ 2 }$. Step 1: Write $ 16x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |
| ④ | Add $ \dfrac{-x^2+50x}{2} $ and $ 30 $ to get $ \dfrac{ \color{purple}{ -x^2+50x+60 } }{ 2 }$. Step 1: Write $ 30 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |