Question
Answer
$$2x\cdot\dfrac{x-2}{x+1}=\dfrac{2x^2-4x}{x+1}$$
Explanation
| $$ \begin{aligned}2x \cdot \frac{x-2}{x+1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2x^2-4x}{x+1}\end{aligned} $$ | |
| ① | Multiply $2x$ by $ \dfrac{x-2}{x+1} $ to get $ \dfrac{ 2x^2-4x }{ x+1 } $. Step 1: Write $ 2x $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 2x \cdot \frac{x-2}{x+1} & \xlongequal{\text{Step 1}} \frac{2x}{\color{red}{1}} \cdot \frac{x-2}{x+1} \xlongequal{\text{Step 2}} \frac{ 2x \cdot \left( x-2 \right) }{ 1 \cdot \left( x+1 \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 2x^2-4x }{ x+1 } \end{aligned} $$ |
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Simplify Rational Expressions