Question
Answer
$$21\cdot\dfrac{x^5}{-3x^3}=\dfrac{21x^5}{-3x^3}$$
Explanation
| $$ \begin{aligned}21 \cdot \frac{x^5}{-3x^3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{21x^5}{-3x^3}\end{aligned} $$ | |
| ① | Multiply $21$ by $ \dfrac{x^5}{-3x^3} $ to get $ \dfrac{ 21x^5 }{ -3x^3 } $. Step 1: Write $ 21 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 21 \cdot \frac{x^5}{-3x^3} & \xlongequal{\text{Step 1}} \frac{21}{\color{red}{1}} \cdot \frac{x^5}{-3x^3} \xlongequal{\text{Step 2}} \frac{ 21 \cdot x^5 }{ 1 \cdot \left( -3x^3 \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 21x^5 }{ -3x^3 } \end{aligned} $$ |
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