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Question

Answer

$$2-\dfrac{x}{3}=\dfrac{-x+6}{3}$$

Explanation
$$ \begin{aligned}2-\frac{x}{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-x+6}{3}\end{aligned} $$
①

Subtract $ \dfrac{x}{3} $ from $ 2 $ to get $ \dfrac{ \color{purple}{ -x+6 } }{ 3 }$.

Step 1: Write $ 2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator.

Step 2: To subtract raitonal expressions, both fractions must have the same denominator.
We can create a common denominator by multiplying the first fraction by $\color{blue}{ 3 }$.

$$ \begin{aligned} 2- \frac{x}{3} & \xlongequal{\text{Step 1}} \frac{2}{\color{red}{1}} - \frac{x}{3} = \frac{ 2 \cdot \color{blue}{ 3 }}{ 1 \cdot \color{blue}{ 3 }} - \frac{ x }{ 3 } = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ \color{purple}{ 6 } }{ 3 } - \frac{ \color{purple}{ x } }{ 3 }=\frac{ \color{purple}{ -x+6 } }{ 3 } \end{aligned} $$
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