Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{2}{x}+\frac{7}{x}-8& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{9}{x}-8 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-8x+9}{x}\end{aligned} $$ | |
| ① | Add $ \dfrac{2}{x} $ and $ \dfrac{7}{x} $ to get $ \dfrac{9}{x} $. To add expressions with the same denominators, we add the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{2}{x} + \frac{7}{x} & = \frac{2}{\color{blue}{x}} + \frac{7}{\color{blue}{x}} =\frac{ 2 + 7 }{ \color{blue}{ x }} = \\[1ex] &= \frac{9}{x} \end{aligned} $$ |
| ② | Subtract $8$ from $ \dfrac{9}{x} $ to get $ \dfrac{ \color{purple}{ -8x+9 } }{ x }$. Step 1: Write $ 8 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |