Tap the blue circles to see an explanation.
| $$ \begin{aligned}14x^3+112 \cdot \frac{x^2}{7}x^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(14+112 \cdot \frac{x^2}{7})x^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(14+\frac{112x^2}{7})x^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{112x^2+98}{7}x^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{112x^5+98x^3}{7}\end{aligned} $$ | |
| ① | Use the distributive property. |
| ② | Multiply $112$ by $ \dfrac{x^2}{7} $ to get $ \dfrac{ 112x^2 }{ 7 } $. Step 1: Write $ 112 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 112 \cdot \frac{x^2}{7} & \xlongequal{\text{Step 1}} \frac{112}{\color{red}{1}} \cdot \frac{x^2}{7} \xlongequal{\text{Step 2}} \frac{ 112 \cdot x^2 }{ 1 \cdot 7 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 112x^2 }{ 7 } \end{aligned} $$ |
| ③ | Add $14$ and $ \dfrac{112x^2}{7} $ to get $ \dfrac{ \color{purple}{ 112x^2+98 } }{ 7 }$. Step 1: Write $ 14 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |
| ④ | Multiply $ \dfrac{112x^2+98}{7} $ by $ x^3 $ to get $ \dfrac{ 112x^5+98x^3 }{ 7 } $. Step 1: Write $ x^3 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{112x^2+98}{7} \cdot x^3 & \xlongequal{\text{Step 1}} \frac{112x^2+98}{7} \cdot \frac{x^3}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( 112x^2+98 \right) \cdot x^3 }{ 7 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 112x^5+98x^3 }{ 7 } \end{aligned} $$ |