Question
Answer
$$12\cdot\dfrac{y}{48}y^3=\dfrac{12y^4}{48}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}12 \cdot \frac{y}{48}y^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{12y}{48}y^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{12y^4}{48}\end{aligned} $$ | |
| ① | Multiply $12$ by $ \dfrac{y}{48} $ to get $ \dfrac{ 12y }{ 48 } $. Step 1: Write $ 12 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 12 \cdot \frac{y}{48} & \xlongequal{\text{Step 1}} \frac{12}{\color{red}{1}} \cdot \frac{y}{48} \xlongequal{\text{Step 2}} \frac{ 12 \cdot y }{ 1 \cdot 48 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 12y }{ 48 } \end{aligned} $$ |
| ② | Multiply $ \dfrac{12y}{48} $ by $ y^3 $ to get $ \dfrac{ 12y^4 }{ 48 } $. Step 1: Write $ y^3 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{12y}{48} \cdot y^3 & \xlongequal{\text{Step 1}} \frac{12y}{48} \cdot \frac{y^3}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 12y \cdot y^3 }{ 48 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 12y^4 }{ 48 } \end{aligned} $$ |
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