Question
Answer
$$1^1\cdot3^3+(14-7)\cdot2=41$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}1^1\cdot3^3+(14-7)\cdot2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}1^1\cdot3^3+7\cdot2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}1^1\cdot3^3+14 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}1\cdot27+14 \xlongequal{ } \\[1 em] & \xlongequal{ }27+14 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}41\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{14} \color{blue}{-7} = \color{blue}{7} $$ |
| ② | $$ 7 \cdot 2 = 14 $$ |
| ③ | A polynomial raised to the power of one equals itself.14-7=7 |
| ④ | Combine like terms: $$ \color{blue}{27} + \color{blue}{14} = \color{blue}{41} $$ |
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