Question
Answer
$$\dfrac{1}{2}(4x-2)x=\dfrac{4x^2-2x}{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{1}{2}(4x-2)x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{4x-2}{2}x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{4x^2-2x}{2}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{1}{2} $ by $ 4x-2 $ to get $ \dfrac{ 4x-2 }{ 2 } $. Step 1: Write $ 4x-2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{1}{2} \cdot 4x-2 & \xlongequal{\text{Step 1}} \frac{1}{2} \cdot \frac{4x-2}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 1 \cdot \left( 4x-2 \right) }{ 2 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 4x-2 }{ 2 } \end{aligned} $$ |
| ② | Multiply $ \dfrac{4x-2}{2} $ by $ x $ to get $ \dfrac{ 4x^2-2x }{ 2 } $. Step 1: Write $ x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{4x-2}{2} \cdot x & \xlongequal{\text{Step 1}} \frac{4x-2}{2} \cdot \frac{x}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( 4x-2 \right) \cdot x }{ 2 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 4x^2-2x }{ 2 } \end{aligned} $$ |
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