Question
Answer
$$-8(x-4)^2=-8x^2+64x-128$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-8(x-4)^2& \xlongequal{ }-8(x^2-8x+16) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(8x^2-64x+128) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-8x^2+64x-128\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{8} $ by $ \left( x^2-8x+16\right) $ $$ \color{blue}{8} \cdot \left( x^2-8x+16\right) = 8x^2-64x+128 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(8x^2-64x+128 \right) = -8x^2+64x-128 $$ |
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