Question
Answer
$$-2y(6x+y-8)=-12xy-2y^2+16y$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-2y(6x+y-8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(12xy+2y^2-16y) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-12xy-2y^2+16y\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2y} $ by $ \left( 6x+y-8\right) $ $$ \color{blue}{2y} \cdot \left( 6x+y-8\right) = 12xy+2y^2-16y $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(12xy+2y^2-16y \right) = -12xy-2y^2+16y $$ |
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Simplify Rational Expressions