| $$ \begin{aligned}-2 \cdot \frac{x}{x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-\frac{2x}{x}\end{aligned} $$ | |
| ① | Multiply $2$ by $ \dfrac{x}{x} $ to get $ \dfrac{ 2x }{ x } $. Step 1: Write $ 2 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 2 \cdot \frac{x}{x} & \xlongequal{\text{Step 1}} \frac{2}{\color{red}{1}} \cdot \frac{x}{x} \xlongequal{\text{Step 2}} \frac{ 2 \cdot x }{ 1 \cdot x } \xlongequal{\text{Step 3}} \frac{ 2x }{ x } \end{aligned} $$ |