Question
Answer
$$-27^3 \cdot \dfrac{y}{9x^4y}=-\dfrac{19683y}{9x^4y}$$
Explanation
| $$ \begin{aligned}-27^3\frac{y}{9x^4y}& \xlongequal{ }-19683 \cdot \frac{y}{9x^4y} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-\frac{19683y}{9x^4y}\end{aligned} $$ | |
| ① | Multiply $19683$ by $ \dfrac{y}{9x^4y} $ to get $ \dfrac{ 19683y }{ 9x^4y } $. Step 1: Write $ 19683 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 19683 \cdot \frac{y}{9x^4y} & \xlongequal{\text{Step 1}} \frac{19683}{\color{red}{1}} \cdot \frac{y}{9x^4y} \xlongequal{\text{Step 2}} \frac{ 19683 \cdot y }{ 1 \cdot 9x^4y } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 19683y }{ 9x^4y } \end{aligned} $$ |
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