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Question

Answer

$$-\dfrac{12}{7}+\dfrac{3}{14}=-\dfrac{21}{14}$$

Explanation
$$ \begin{aligned}-\frac{12}{7}+\frac{3}{14}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-\frac{21}{14}\end{aligned} $$
①

Add $ \dfrac{-12}{7} $ and $ \dfrac{3}{14} $ to get $ \dfrac{ \color{purple}{ -21 } }{ 14 }$.

To add fractions they must have the same denominator.
We can create a common denominator by multiplying the first fraction by $\color{blue}{ 2 }$.

$$ \begin{aligned} \frac{-12}{7} + \frac{3}{14} & = \frac{ \left( -12 \right) \cdot \color{blue}{ 2 }}{ 7 \cdot \color{blue}{ 2 }} + \frac{ 3 }{ 14 } = \\[1ex] &=\frac{ \color{purple}{ -24 } }{ 14 } + \frac{ \color{purple}{ 3 } }{ 14 }=\frac{ \color{purple}{ -21 } }{ 14 } \end{aligned} $$
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