Question
Answer
$$-\dfrac{1}{3}+\dfrac{4}{3}=1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-\frac{1}{3}+\frac{4}{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3}{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}} \frac{ 3 : \color{orangered}{ 3 } }{ 3 : \color{orangered}{ 3 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{1}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}1\end{aligned} $$ | |
| ① | Add $ \dfrac{-1}{3} $ and $ \dfrac{4}{3} $ to get $ \dfrac{3}{3} $. To add expressions with the same denominators, we add the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{-1}{3} + \frac{4}{3} & = \frac{-1}{\color{blue}{3}} + \frac{4}{\color{blue}{3}} =\frac{ -1 + 4 }{ \color{blue}{ 3 }} = \\[1ex] &= \frac{3}{3} \end{aligned} $$ |
| ② | Divide both the top and bottom numbers by $ \color{orangered}{ 3 } $. |
| ③ | Remove 1 from denominator. |
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