Question
Answer
$$-\dfrac{5x^2+16x+4}{(x-1)(x+4)}=\dfrac{-5x^2-16x-4}{x^2+3x-4}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-\frac{5x^2+16x+4}{(x-1)(x+4)}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-\frac{5x^2+16x+4}{x^2+4x-x-4} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-5x^2-16x-4}{x^2+3x-4}\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-1}\right) $ by each term in $ \left( x+4\right) $. $$ \left( \color{blue}{x-1}\right) \cdot \left( x+4\right) = x^2+4x-x-4 $$ |
| ② | Simplify denominator $$ x^2+ \color{blue}{4x} \color{blue}{-x} -4 = x^2+ \color{blue}{3x} -4 $$ |
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Simplify Rational Expressions