Question
Answer
$$(x^2-5x-36)(x^2-2x-63)=x^4-7x^3-89x^2+387x+2268$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x^2-5x-36)(x^2-2x-63)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^4-7x^3-89x^2+387x+2268\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x^2-5x-36}\right) $ by each term in $ \left( x^2-2x-63\right) $. $$ \left( \color{blue}{x^2-5x-36}\right) \cdot \left( x^2-2x-63\right) = x^4-2x^3-63x^2-5x^3+10x^2+315x-36x^2+72x+2268 $$ |
| ② | Combine like terms: $$ x^4 \color{blue}{-2x^3} \color{red}{-63x^2} \color{blue}{-5x^3} + \color{green}{10x^2} + \color{orange}{315x} \color{green}{-36x^2} + \color{orange}{72x} +2268 = \\ = x^4 \color{blue}{-7x^3} \color{green}{-89x^2} + \color{orange}{387x} +2268 $$ |
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