Question
Answer
$$\dfrac{y^2+9y+14}{6y^2-24}=\dfrac{y+7}{6y-12}$$
Explanation
| $$ \begin{aligned}\frac{y^2+9y+14}{6y^2-24}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{y+7}{6y-12}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{y^2+9y+14}{6y^2-24} $ to $ \dfrac{y+7}{6y-12} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{y+2}$. $$ \begin{aligned} \frac{y^2+9y+14}{6y^2-24} & =\frac{ \left( y+7 \right) \cdot \color{blue}{ \left( y+2 \right) }}{ \left( 6y-12 \right) \cdot \color{blue}{ \left( y+2 \right) }} = \\[1ex] &= \frac{y+7}{6y-12} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions