Question
Answer
$$\dfrac{y^2+7y+12}{y^2+12y+27}=\dfrac{y+4}{y+9}$$
Explanation
| $$ \begin{aligned}\frac{y^2+7y+12}{y^2+12y+27}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{y+4}{y+9}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{y^2+7y+12}{y^2+12y+27} $ to $ \dfrac{y+4}{y+9} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{y+3}$. $$ \begin{aligned} \frac{y^2+7y+12}{y^2+12y+27} & =\frac{ \left( y+4 \right) \cdot \color{blue}{ \left( y+3 \right) }}{ \left( y+9 \right) \cdot \color{blue}{ \left( y+3 \right) }} = \\[1ex] &= \frac{y+4}{y+9} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions