| $$ \begin{aligned}\frac{y^2+2y}{45}y& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{y^3+2y^2}{45}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{y^2+2y}{45} $ by $ y $ to get $ \dfrac{ y^3+2y^2 }{ 45 } $. Step 1: Write $ y $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{y^2+2y}{45} \cdot y & \xlongequal{\text{Step 1}} \frac{y^2+2y}{45} \cdot \frac{y}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( y^2+2y \right) \cdot y }{ 45 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ y^3+2y^2 }{ 45 } \end{aligned} $$ |