Question
Answer
$$\dfrac{y^2-11y+30}{y^2-13y+40}=\dfrac{y-6}{y-8}$$
Explanation
| $$ \begin{aligned}\frac{y^2-11y+30}{y^2-13y+40}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{y-6}{y-8}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{y^2-11y+30}{y^2-13y+40} $ to $ \dfrac{y-6}{y-8} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{y-5}$. $$ \begin{aligned} \frac{y^2-11y+30}{y^2-13y+40} & =\frac{ \left( y-6 \right) \cdot \color{blue}{ \left( y-5 \right) }}{ \left( y-8 \right) \cdot \color{blue}{ \left( y-5 \right) }} = \\[1ex] &= \frac{y-6}{y-8} \end{aligned} $$ |
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Simplify Rational Expressions