| $$ \begin{aligned}\frac{y^2-10y+25}{y-5}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}y-5\end{aligned} $$ | |
| ① | Simplify $ \dfrac{y^2-10y+25}{y-5} $ to $ y-5$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{y-5}$. $$ \begin{aligned} \frac{y^2-10y+25}{y-5} & =\frac{ \left( y-5 \right) \cdot \color{blue}{ \left( y-5 \right) }}{ 1 \cdot \color{blue}{ \left( y-5 \right) }} = \\[1ex] &= \frac{y-5}{1} =y-5 \end{aligned} $$ |