| $$ \begin{aligned}\frac{x+2}{4(x+1)}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x+2}{4x+4}\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4} $ by $ \left( x+1\right) $ $$ \color{blue}{4} \cdot \left( x+1\right) = 4x+4 $$ |