Question
Answer
$$\dfrac{(x+1)^2}{x-8x^2+5x+50}=\dfrac{x^2+2x+1}{-8x^2+6x+50}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{(x+1)^2}{x-8x^2+5x+50}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{x^2+2x+1}{-8x^2+6x+50}\end{aligned} $$ | |
| ① | Find $ \left(x+1\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ x } $ and $ B = \color{red}{ 1 }$. $$ \begin{aligned}\left(x+1\right)^2 = \color{blue}{x^2} +2 \cdot x \cdot 1 + \color{red}{1^2} = x^2+2x+1\end{aligned} $$ |
| ② | Combine like terms: $$ \color{blue}{x} -8x^2+ \color{blue}{5x} +50 = -8x^2+ \color{blue}{6x} +50 $$ |
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