| $$ \begin{aligned}\frac{x-2}{x+9x-5}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x-2}{10x-5}\end{aligned} $$ | |
| ① | Simplify denominator $$ \color{blue}{x} + \color{blue}{9x} -5 = \color{blue}{10x} -5 $$ |