Question
Answer
$$\dfrac{x^4+7x^3}{2x^2+14x}=\dfrac{x^2}{2}$$
Explanation
| $$ \begin{aligned}\frac{x^4+7x^3}{2x^2+14x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^2}{2}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{x^4+7x^3}{2x^2+14x} $ to $ \dfrac{x^2}{2} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x^2+7x}$. $$ \begin{aligned} \frac{x^4+7x^3}{2x^2+14x} & =\frac{ x^2 \cdot \color{blue}{ \left( x^2+7x \right) }}{ 2 \cdot \color{blue}{ \left( x^2+7x \right) }} = \\[1ex] &= \frac{x^2}{2} \end{aligned} $$ |
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Simplify Rational Expressions