Question
Answer
$$\dfrac{x^2+x-6}{x^2+3x-10}=\dfrac{x+3}{x+5}$$
Explanation
| $$ \begin{aligned}\frac{x^2+x-6}{x^2+3x-10}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x+3}{x+5}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{x^2+x-6}{x^2+3x-10} $ to $ \dfrac{x+3}{x+5} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x-2}$. $$ \begin{aligned} \frac{x^2+x-6}{x^2+3x-10} & =\frac{ \left( x+3 \right) \cdot \color{blue}{ \left( x-2 \right) }}{ \left( x+5 \right) \cdot \color{blue}{ \left( x-2 \right) }} = \\[1ex] &= \frac{x+3}{x+5} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions