Question
Answer
$$\dfrac{x^2+6+5}{x^2-3x-4}=\dfrac{x^2+11}{x^2-3x-4}$$
Explanation
| $$ \begin{aligned}\frac{x^2+6+5}{x^2-3x-4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^2+11}{x^2-3x-4}\end{aligned} $$ | |
| ① | Simplify numerator $$ x^2+ \color{blue}{6} + \color{blue}{5} = x^2+ \color{blue}{11} $$ |
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Simplify Rational Expressions