Question
Answer
$$\dfrac{x^2+16x+63}{x^2-2x-63}=\dfrac{x+9}{x-9}$$
Explanation
| $$ \begin{aligned}\frac{x^2+16x+63}{x^2-2x-63}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x+9}{x-9}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{x^2+16x+63}{x^2-2x-63} $ to $ \dfrac{x+9}{x-9} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x+7}$. $$ \begin{aligned} \frac{x^2+16x+63}{x^2-2x-63} & =\frac{ \left( x+9 \right) \cdot \color{blue}{ \left( x+7 \right) }}{ \left( x-9 \right) \cdot \color{blue}{ \left( x+7 \right) }} = \\[1ex] &= \frac{x+9}{x-9} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions