Question
Answer
$$\dfrac{x^2+11x+24}{(x-5)(x-6)}=\dfrac{x^2+11x+24}{x^2-11x+30}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{x^2+11x+24}{(x-5)(x-6)}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^2+11x+24}{x^2-6x-5x+30} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{x^2+11x+24}{x^2-11x+30}\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-5}\right) $ by each term in $ \left( x-6\right) $. $$ \left( \color{blue}{x-5}\right) \cdot \left( x-6\right) = x^2-6x-5x+30 $$ |
| ② | Simplify denominator $$ x^2 \color{blue}{-6x} \color{blue}{-5x} +30 = x^2 \color{blue}{-11x} +30 $$ |
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Simplify Rational Expressions