Question
Answer
$$\dfrac{x^2-9x+14}{x^2-2x}=\dfrac{x-7}{x}$$
Explanation
| $$ \begin{aligned}\frac{x^2-9x+14}{x^2-2x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x-7}{x}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{x^2-9x+14}{x^2-2x} $ to $ \dfrac{x-7}{x} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x-2}$. $$ \begin{aligned} \frac{x^2-9x+14}{x^2-2x} & =\frac{ \left( x-7 \right) \cdot \color{blue}{ \left( x-2 \right) }}{ x \cdot \color{blue}{ \left( x-2 \right) }} = \\[1ex] &= \frac{x-7}{x} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions