Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x^2-9)\frac{x^2+3a+9}{x^4}\frac{x^{10}}{x^3}-81& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^4+3ax^2-27a-81}{x^4}\frac{x^{10}}{x^3}-81 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{x^{14}+3ax^{12}-27ax^{10}-81x^{10}}{x^7}-81 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{x^{14}+3ax^{12}-27ax^{10}-81x^{10}-81x^7}{x^7}\end{aligned} $$ | |
| ① | Multiply $x^2-9$ by $ \dfrac{x^2+3a+9}{x^4} $ to get $ \dfrac{x^4+3ax^2-27a-81}{x^4} $. Step 1: Write $ x^2-9 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} x^2-9 \cdot \frac{x^2+3a+9}{x^4} & \xlongequal{\text{Step 1}} \frac{x^2-9}{\color{red}{1}} \cdot \frac{x^2+3a+9}{x^4} \xlongequal{\text{Step 2}} \frac{ \left( x^2-9 \right) \cdot \left( x^2+3a+9 \right) }{ 1 \cdot x^4 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ x^4+3ax^2+ \cancel{9x^2} -\cancel{9x^2}-27a-81 }{ x^4 } = \frac{x^4+3ax^2-27a-81}{x^4} \end{aligned} $$ |
| ② | Multiply $ \dfrac{x^4+3ax^2-27a-81}{x^4} $ by $ \dfrac{x^{10}}{x^3} $ to get $ \dfrac{ x^{14}+3ax^{12}-27ax^{10}-81x^{10} }{ x^7 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{x^4+3ax^2-27a-81}{x^4} \cdot \frac{x^{10}}{x^3} & \xlongequal{\text{Step 1}} \frac{ \left( x^4+3ax^2-27a-81 \right) \cdot x^{10} }{ x^4 \cdot x^3 } = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ x^{14}+3ax^{12}-27ax^{10}-81x^{10} }{ x^7 } \end{aligned} $$ |
| ③ | Subtract $81$ from $ \dfrac{x^{14}+3ax^{12}-27ax^{10}-81x^{10}}{x^7} $ to get $ \dfrac{ \color{purple}{ x^{14}+3ax^{12}-27ax^{10}-81x^{10}-81x^7 } }{ x^7 }$. Step 1: Write $ 81 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |