Question
Answer
$$\dfrac{x^2-9}{x^2-6+9}=\dfrac{x^2-9}{x^2+3}$$
Explanation
| $$ \begin{aligned}\frac{x^2-9}{x^2-6+9}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^2-9}{x^2+3}\end{aligned} $$ | |
| ① | Simplify denominator $$ x^2 \color{blue}{-6} + \color{blue}{9} = x^2+ \color{blue}{3} $$ |
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Simplify Rational Expressions