Question
Answer
$$\dfrac{x^2-4}{x^2+7-18}=\dfrac{x^2-4}{x^2-11}$$
Explanation
| $$ \begin{aligned}\frac{x^2-4}{x^2+7-18}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^2-4}{x^2-11}\end{aligned} $$ | |
| ① | Simplify denominator $$ x^2+ \color{blue}{7} \color{blue}{-18} = x^2 \color{blue}{-11} $$ |
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Simplify Rational Expressions