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Question

Answer

$$\dfrac{x^2}{25}-\dfrac{x}{5}=\dfrac{x^2-5x}{25}$$

Explanation
$$ \begin{aligned}\frac{x^2}{25}-\frac{x}{5}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^2-5x}{25}\end{aligned} $$
①

Subtract $ \dfrac{x}{5} $ from $ \dfrac{x^2}{25} $ to get $ \dfrac{ \color{purple}{ x^2-5x } }{ 25 }$.

To subtract raitonal expressions, both fractions must have the same denominator.
We can create a common denominator by multiplying the second fraction by $\color{blue}{5}$.

$$ \begin{aligned} \frac{x^2}{25} - \frac{x}{5} & = \frac{ x^2 }{ 25 } - \frac{ x \cdot \color{blue}{ 5 }}{ 5 \cdot \color{blue}{ 5 }} = \\[1ex] &=\frac{ \color{purple}{ x^2 } }{ 25 } - \frac{ \color{purple}{ 5x } }{ 25 }=\frac{ \color{purple}{ x^2-5x } }{ 25 } \end{aligned} $$
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