Question
Answer
$$(w-3)(4w+1)=4w^2-11w-3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(w-3)(4w+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4w^2+w-12w-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4w^2-11w-3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{w-3}\right) $ by each term in $ \left( 4w+1\right) $. $$ \left( \color{blue}{w-3}\right) \cdot \left( 4w+1\right) = 4w^2+w-12w-3 $$ |
| ② | Combine like terms: $$ 4w^2+ \color{blue}{w} \color{blue}{-12w} -3 = 4w^2 \color{blue}{-11w} -3 $$ |
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