| $$ \begin{aligned}\frac{u^2-14u+49}{u-7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}u-7\end{aligned} $$ | |
| ① | Simplify $ \dfrac{u^2-14u+49}{u-7} $ to $ u-7$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{u-7}$. $$ \begin{aligned} \frac{u^2-14u+49}{u-7} & =\frac{ \left( u-7 \right) \cdot \color{blue}{ \left( u-7 \right) }}{ 1 \cdot \color{blue}{ \left( u-7 \right) }} = \\[1ex] &= \frac{u-7}{1} =u-7 \end{aligned} $$ |