Question
Answer
$$\dfrac{s^2-16}{s^2-8s+16}=\dfrac{s+4}{s-4}$$
Explanation
| $$ \begin{aligned}\frac{s^2-16}{s^2-8s+16}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{s+4}{s-4}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{s^2-16}{s^2-8s+16} $ to $ \dfrac{s+4}{s-4} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{s-4}$. $$ \begin{aligned} \frac{s^2-16}{s^2-8s+16} & =\frac{ \left( s+4 \right) \cdot \color{blue}{ \left( s-4 \right) }}{ \left( s-4 \right) \cdot \color{blue}{ \left( s-4 \right) }} = \\[1ex] &= \frac{s+4}{s-4} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions