Question
Answer
$$\dfrac{q-10}{q^2-10q}=\dfrac{1}{q}$$
Explanation
| $$ \begin{aligned}\frac{q-10}{q^2-10q}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{1}{q}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{q-10}{q^2-10q} $ to $ \dfrac{1}{q} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{q-10}$. $$ \begin{aligned} \frac{q-10}{q^2-10q} & =\frac{ 1 \cdot \color{blue}{ \left( q-10 \right) }}{ q \cdot \color{blue}{ \left( q-10 \right) }} = \\[1ex] &= \frac{1}{q} \end{aligned} $$ |
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Simplify Rational Expressions