Question
Answer
$$\dfrac{p^2+8p+12}{p+6}=p+2$$
Explanation
| $$ \begin{aligned}\frac{p^2+8p+12}{p+6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}p+2\end{aligned} $$ | |
| ① | Simplify $ \dfrac{p^2+8p+12}{p+6} $ to $ p+2$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{p+6}$. $$ \begin{aligned} \frac{p^2+8p+12}{p+6} & =\frac{ \left( p+2 \right) \cdot \color{blue}{ \left( p+6 \right) }}{ 1 \cdot \color{blue}{ \left( p+6 \right) }} = \\[1ex] &= \frac{p+2}{1} =p+2 \end{aligned} $$ |
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Simplify Rational Expressions