Question
Answer
$$\dfrac{n^2+7n+10}{n^2+2n-15}=\dfrac{n+2}{n-3}$$
Explanation
| $$ \begin{aligned}\frac{n^2+7n+10}{n^2+2n-15}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{n+2}{n-3}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{n^2+7n+10}{n^2+2n-15} $ to $ \dfrac{n+2}{n-3} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{n+5}$. $$ \begin{aligned} \frac{n^2+7n+10}{n^2+2n-15} & =\frac{ \left( n+2 \right) \cdot \color{blue}{ \left( n+5 \right) }}{ \left( n-3 \right) \cdot \color{blue}{ \left( n+5 \right) }} = \\[1ex] &= \frac{n+2}{n-3} \end{aligned} $$ |
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Simplify Rational Expressions