Question
Answer
$$\dfrac{n^2+5n-6}{n^2+16n+60}=\dfrac{n-1}{n+10}$$
Explanation
| $$ \begin{aligned}\frac{n^2+5n-6}{n^2+16n+60}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{n-1}{n+10}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{n^2+5n-6}{n^2+16n+60} $ to $ \dfrac{n-1}{n+10} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{n+6}$. $$ \begin{aligned} \frac{n^2+5n-6}{n^2+16n+60} & =\frac{ \left( n-1 \right) \cdot \color{blue}{ \left( n+6 \right) }}{ \left( n+10 \right) \cdot \color{blue}{ \left( n+6 \right) }} = \\[1ex] &= \frac{n-1}{n+10} \end{aligned} $$ |
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Simplify Rational Expressions