Question
Answer
$$\dfrac{n^2+3n-70}{n^2-15n+56}=\dfrac{n+10}{n-8}$$
Explanation
| $$ \begin{aligned}\frac{n^2+3n-70}{n^2-15n+56}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{n+10}{n-8}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{n^2+3n-70}{n^2-15n+56} $ to $ \dfrac{n+10}{n-8} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{n-7}$. $$ \begin{aligned} \frac{n^2+3n-70}{n^2-15n+56} & =\frac{ \left( n+10 \right) \cdot \color{blue}{ \left( n-7 \right) }}{ \left( n-8 \right) \cdot \color{blue}{ \left( n-7 \right) }} = \\[1ex] &= \frac{n+10}{n-8} \end{aligned} $$ |
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Simplify Rational Expressions